25c^2+20ct+4t^2=0

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Solution for 25c^2+20ct+4t^2=0 equation:


Simplifying
25c2 + 20ct + 4t2 = 0

Reorder the terms:
20ct + 25c2 + 4t2 = 0

Solving
20ct + 25c2 + 4t2 = 0

Solving for variable 'c'.

Factor a trinomial.
(5c + 2t)(5c + 2t) = 0

Subproblem 1

Set the factor '(5c + 2t)' equal to zero and attempt to solve: Simplifying 5c + 2t = 0 Solving 5c + 2t = 0 Move all terms containing c to the left, all other terms to the right. Add '-2t' to each side of the equation. 5c + 2t + -2t = 0 + -2t Combine like terms: 2t + -2t = 0 5c + 0 = 0 + -2t 5c = 0 + -2t Remove the zero: 5c = -2t Divide each side by '5'. c = -0.4t Simplifying c = -0.4t

Subproblem 2

Set the factor '(5c + 2t)' equal to zero and attempt to solve: Simplifying 5c + 2t = 0 Solving 5c + 2t = 0 Move all terms containing c to the left, all other terms to the right. Add '-2t' to each side of the equation. 5c + 2t + -2t = 0 + -2t Combine like terms: 2t + -2t = 0 5c + 0 = 0 + -2t 5c = 0 + -2t Remove the zero: 5c = -2t Divide each side by '5'. c = -0.4t Simplifying c = -0.4t

Solution

c = {-0.4t, -0.4t}

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